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$ (\sqrt{19}),K=$"
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$ (\sqrt{11}+\sqrt{13}),K=$"
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$ (\sqrt[3]{11}, \omega), \quad K=$](img20.png)
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$ (\omega=\dfrac{-1+\sqrt{-3}}{2}$"
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$ (\sqrt[4]{3}, \sqrt{-1})$](img29.png)
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2010-12-28